Aptitude tests assess the capability of a candidate to practice fundamentals to clear up complicated situations. Every query is nothing but a scenario in which you are supposed to clear up with a fundamental grasp of maths. In the class, college students have seldom chance to experience the actual lifestyle conditions whilst on a job this is something which is required all the time.
So, this article will discuss one essential part of the aptitude test which is calendars. There are several approaches to resolve calendar-based problems. But the traditional techniques take a lot of time, which can be crucial in a time-restricted test. In this article, we will study an aptitude short trick to find the birthday of any date.

### 1  4  4  0  2  5  0  3  6  1  4  6

You can remember the above sequence by breaking into pair of 3.

144, 025, 036 and 146.

122 = 144

52 =  025

62 =  036

146 = 144+2

These all numbers represent months of a year

Check the century the year belongs to and assign following values as shown below

And for days, assign the following day code values

Example 1:

Let the date be 5th April 1990 (5-4-1989)

Step 1: Write the equation in following format

Date + Month Code + Century code + Last 2 digits of year + (Quotient of (Last 2 digits of year/4))

The date is 05-04-1989

According to above equation we write it as

05 + 0 (April Month Code) +0 (19th Century code) + 89 (last 2 digits of year 1989) + 22 (89/4 =22 and reminder =1. Discard remainder)

Step 2:

Divide the addition result by 7 and check reminder.

In this case while you perform 116/7 you will get quotient =16 and remainder = 4.

Step 3: Neglect quotient and consider remainder. Compare the remainder value with day code given above.

Here remainder =4 which corresponds to Wednesday.

Therefore the day of date 5th April 1989 is Wednesday

Example 2:

Date : 21st September 1965

Date + Month Code + Century code + Last 2 digits of year + (Quotient of (Last 2 digits of year/4))

The above equation can be written as

21+ 6 (September Month Code) + 0 (19th Century code) + 65 (last 2 digits of year 1965) + 16(65/4 =22 and reminder =1. Discard remainder)

Step 2:

Divide the addition result by 7 and check reminder.

In this case while you perform 108/7 you will get quotient =15 and remainder = 3.

Step 3: Neglect quotient and take remainder. Compare the remainder value with day code given above.

Here remainder =3 which corresponds to Tuesday.

Therefore the day of date 21st September 1965 is Tuesday.

Aptitude short trick to find out the birth day of any date (Vedic Maths Trick)